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A student calculated the percent by mass of water in a sample of BaCl2·2H2O to be 16.4%, but the accepted value is 14.8%. What was the student's percent error? a) 10.81% b) 11.89% c) 9.46% d) 10.00%

2 Answers

4 votes

Final answer:

The student's percent error is 10.81%.

Step-by-step explanation:

The student's percent error can be calculated using the formula:

Percent Error = |(Experimental Value - Accepted Value) / Accepted Value| x 100%

In this case, the student's experimental value is 16.4% and the accepted value is 14.8%.

Percent Error = |(16.4 - 14.8) / 14.8| x 100% = 10.81%

Therefore, the student's percent error is 10.81%.

User Archit Verma
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7.6k points
5 votes

The student's percent error is 10.81%. OPtion A.

Percent error is a measure of the accuracy of an experiment or measurement. It's calculated by comparing the experimental value to the accepted value, and expressing the difference as a percentage of the accepted value.

The percent error can be calculated using the formula:


$$\text{Percent Error} = \left| \frac{\text{Experimental Value} - \text{Accepted Value}}{\text{Accepted Value}} \right| * 100\%$$

We can calculate the percent error for the student by substituting the given values into the formula:


$$\text{Percent Error} = \left| (16.4\% - 14.8\%)/(14.8\%) \right| * 100\% = 10.81\%$$

So, the student's percent error is 10.81%. Therefore, the correct answer is a) 10.81%.

User Tom Van Rossom
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7.5k points