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A compound contains only carbon and hydrogen and has a formula mass of 28.06 amu. What is the molecular formula of the compound? Express your answer as a chemical formula. A chemical reaction does not occur for this question.

User Actaram
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Final answer:

To find the molecular formula of a compound given its percent composition and molecular mass, determine the empirical formula and the number of empirical formula units. Multiply the subscripts in the empirical formula by the number of empirical formula units to get the molecular formula.

Step-by-step explanation:

The molecular formula of a compound can be determined from its percent composition and molecular mass. To find the molecular formula of the compound with a percent composition of 49.47% C, 5.201% H, 28.84% N, and 16.48% O, and a molecular mass of 194.2 amu, first find the empirical formula. Convert the percent composition to grams, find the moles of each element, and divide by the smallest number of moles to get the empirical formula. Then, divide the molecular mass by the empirical formula mass to find the number of empirical formula units. Multiply the subscripts in the empirical formula by the number of empirical formula units to get the molecular formula.



For example, for the compound in question, if we assume a 100 g sample, we have 49.47 g C, 5.201 g H, 28.84 g N, and 16.48 g O. Converting these masses to moles, we have 4.120 moles C, 5.160 moles H, 2.071 moles N, and 1.030 moles O. Dividing these moles by the smallest number of moles (2.071), we get a ratio of approximately 2:2.5:1:0.5. We can multiply these ratios by a common factor to obtain whole numbers, which gives us an empirical formula of C4H5NO2. The empirical formula has a formula mass of 99.09 amu. Dividing the molecular mass (194.2 amu) by the empirical formula mass (99.09 amu) gives us approximately 1.96. Multiply the subscripts in the empirical formula by 2 to obtain the molecular formula, which is C8H10N2O4.

User Sarkis Arutiunian
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The molecular formula of the compound is
C_2H_4.

The atomic mass of carbon (C) is roughly 12.01 g/mol, and the atomic mass of hydrogen (H) is approximately 1.008 g/mol.

With a compound composed solely of carbon and hydrogen and a formula mass of 28.06 amu, potential molecular formulas include
CH_4(Methane) with a molecular mass of about 16.04 g/mol,
C_2H_2(Acetylene) with a molecular mass of around 26.04 g/mol,
C_2H_4(Ethylene) with a molecular mass of approximately 28.05 g/mol, and
C_2H_6 (Ethane) with a molecular mass of about 30.07 g/mol.

The molecular formula that aligns most closely with the specified formula mass of 28.06 amu is
C_2H_4.

User Simon Heinzle
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