Step-by-step explanation:
Three resistors of resistances 2ohm,3ohm, and 6ohm respectively.
Let R1=2Ω
⇒R2=3Ω
⇒R2=6Ω
● A total resistance of 4Ω from three resistors of given resistances. Firstly, connect the two resistors of 3Ω and 6Ω in parallel to get a total resistance of 2Ω which is less than the lowest individual resistance.
●When R 2 and R 3 are connected in parallel with
R1 in series we get
⇒1/R=1/R2+1/R3
⇒1/R=1/3+1/6
⇒1/R=1/2
⇒R=2Ω
●Hence, the total resistance of the circuit is 4Ω.