37 students take both languages.
To solve this problem, let's use algebra and step through it logically. We'll use these variables:
- Let C be the number of students taking Chinese.
- Let S be the number of students taking Spanish.
- Let B be the number of students taking both languages.
From the problem, we know:
1. Total number of students: C + S - B = 97 (subtract B to avoid double-counting the students who take both languages).
2. There are 8 more students in Chinese than in Spanish: C = S + 8 .
3. 26 students take only Spanish: S - B = 26 (since S includes students who take both).
Now, let's solve these equations step by step.
Step 1: Substitute C from Equation 2 into Equation 1
Since C = S + 8 , we can replace C in Equation 1:
S + 8 + S - B = 97
2S + 8 - B = 97
Step 2: Solve for B using Equations 3 and the modified Equation 1**
From Equation 3, B = S - 26 Substitute this into the modified Equation 1:
2S + 8 - (S - 26) = 97
2S + 8 - S + 26 = 97
S + 34 = 97
Now, let's solve for S :
S = 97 - 34
S = 63
Step 3: Find B using the value of S from Equation 3
B = S - 26
B = 63 - 26
B = 37