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Write the equation of the line that passes through the point P (3, 4) and is perpendicular to the line y = -5x + 8. a)y=1/5x +8 b)y=1/5x +4.6 c)y=1/5x +3.4 d)x=3.4y +1/5 e)y=x +3/4

User Arendjr
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First, let's establish what we know. We know that the line we're trying to find is perpendicular to the line given by the equation y = -5x + 8 and it passes through the point P(3,4).

We also know that for a line to be perpendicular to another, the product of their slopes must equal -1. This is a fundamental property of perpendicular lines in a coordinate system.

So, given that we have the slope of the initial line (which is -5), we can calculate the slope of the line that's perpendicular to it by taking the negative reciprocal of the initial slope.

That is, slope_required = -1/slope_given = -1/(-5) = 1/5 = 0.2

Now, we know the slope of the line (m) we're looking for and we also have a point (x, y) that lies on our line. We can use these to compute the y-intercept (c) of our line by rearranging the formula for a line, y = mx + c.

We substitute m = 1/5, x = 3, and y = 4 into the equation to get 4 = 1/5 * 3 + c.

Solving this equation for c gives us c = 4 - 1/5 * 3 = 3.4

So, the equation of the line that is perpendicular to y = -5x + 8 and passes through the point P(3, 4) is y = 1/5 * x + 3.4.

Therefore, the correct choice is option c) y = 1/5 * x + 3.4.

User Igoranze
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