Answer:
A∈ (AC)
∠RAC=180°
B∈(AP)
∠ABP=180°
∠ABC=180-2x
C∈QB
∠ACB = 180-3x
in ACB :
180-4x+180-2x+180-3x=180
540-9x=180
-9x=180-540
-9x=-360
x=40°
∠RAB = 4x= 160°
∠CBP = 80°
∠ACQ = 120°
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