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A 400 gram mass, hung on a spring, causes the spring to stretch 2.0 cm. The spring constant is?

User Haoming
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1 Answer

4 votes

Answer:

196.2 N/m.

Step-by-step explanation:

To find the spring constant (k), you can use Hooke's Law, which relates the force exerted by a spring to its spring constant and the displacement from its equilibrium position.

The formula for Hooke's Law is:

F = -k * x

Where:

- F is the force applied to the spring (in newtons, N).

- k is the spring constant (in newton per meter, N/m).

- x is the displacement from the equilibrium position (in meters, m).

First, you need to convert the mass from grams to kilograms:

400 grams = 0.4 kg

Now, you can calculate the force (F) acting on the spring due to the mass:

F = m * g

Where:

- m is the mass (0.4 kg).

- g is the acceleration due to gravity (approximately 9.81 m/s²).

F = 0.4 kg * 9.81 m/s² = 3.924 N

Now, you have the force (F) and the displacement (x) is 2.0 cm, which you need to convert to meters (since 1 cm = 0.01 m):

x = 2.0 cm * 0.01 m/cm = 0.02 m

Now, you can use Hooke's Law to find the spring constant (k):

3.924 N = -k * 0.02 m

Solve for k:

k = -3.924 N / 0.02 m

k = -196.2 N/m

The spring constant is approximately 196.2 N/m. Note that the negative sign indicates that the force exerted by the spring is in the opposite direction of the displacement, which is a convention in Hooke's Law.

User Natallia
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