Question

A jogger moving at +2.4 meters per second accelerates at a rate of +1.6 meters per second^2 while traveling +5.0 meters.

calculate the final velocity​

Answer 1

Using the 3rd equation of motion:

`\sf {v}^(2) - {u}^(2) = 2as`

We have;

• u = 2.4 m/s
• a = 1.6m/s^2
• s = 5 m

`\sf {v}^(2) - {2.4}^(2) = 2 * 1.6 * 5`

`\sf {v}^(2) = 2 * 1.6 * 5 + {2.4}^(2)`

`\sf {v}^(2) = 16 + 5.76`

`\sf v = √(21.76)`

`\sf v \approx 4.66 \:m {s}^( - 1)`