Question

The sum of three numbers is 66 the third number is two times the second number the first number is six more than the second what are the numbers

Answer 1

15 , 21 , 30

Explanation:

let the second number be n , then

the first number is n + 6 ( 6 more than the second number )

the third number is 2n ( two times the second number )

sum the 3 numbers, equate to 66 and solve for n

n + 6 + n + 2n = 66 ( simplify left side )

4n + 6 = 66 ( subtract 6 from both sides )

4n = 60 (divide both sides by 4 )

n = 15 ← second number

n + 6 = 15 + 6 = 21 ← first number

2n = 2 × 15 = 30 ← third number