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Given that
9^x = (27ª) 1/2 x 3^b
find an expression for x in
terms of a and b.

1 Answer

1 vote

Answer:

To find an expression for x in terms of a and b, we need to simplify the given equation and isolate x.

Let's start by rewriting the equation using the properties of exponents:

9^x = (27^a)^(1/2) * 3^b

Since (27^a)^(1/2) is equal to the square root of 27^a, we can simplify further:

9^x = √(27^a) * 3^b

Now, let's simplify the expression inside the square root:

√(27^a) = √((3^3)^a) = √(3^(3a)) = (3^(3a))^(1/2) = 3^(3a/2)

Plugging this back into the equation, we have:

9^x = 3^(3a/2) * 3^b

To combine the terms on the right side of the equation, we add the exponents of 3:

9^x = 3^(3a/2 + b)

Now, we can rewrite 9^x as (3^2)^x = 3^(2x) to match the base:

3^(2x) = 3^(3a/2 + b)

Since the bases are the same, the exponents must be equal:

2x = 3a/2 + b

Finally, we can solve for x by dividing both sides of the equation by 2:

x = (3a/2 + b) / 2

Therefore, the expression for x in terms of a and b is:

x = (3a/2 + b) / 2

I hope this explanation helps!

Explanation:

User Gunan
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