Question

a force F is pulling horizontally a box to the right with 30N, friction acting on the box is 10N. the box moves for 4 m along the horizontal floor determine the work done on the box

Answer 1

The work done on the box is the product of the net force acting on the box and the displacement of the box. The net force acting on the box is the difference between the applied force F and the friction force f, which is 30 N - 10 N = 20 N. The displacement of the box is 4 m. Therefore, the work done on the box is 20 N x 4 m = 80 J. This means that the box gains 80 J of kinetic energy as it moves along the floor.