Question

A machine packages bags of almonds. The weights of the bags are normally distributed with a mean of 14 ounces and a standard deviation of 1.2 ounces.

What is the z-score of a bag of almonds that weighs 12.2 ounces?

Answer 1

-1.67

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To find the z-score of a bag of almonds that weighs 12.2 ounces, you can use the formula:

• z = (x - μ) / σ,

where

• x is the value you want to find the z-score for,
• μ is the mean, and
• σ is the standard deviation.

Plugging in the values:

• z = (12.2 - 14) / 1.2
• z = - 1.67

So, the z-score of a bag of almonds weighing 12.2 ounces is -1.67.