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1/3 |x-3| +4=10
What’s this I need help please !!

2 Answers

1 vote

Answer:

21 and -15

Explanation:

The equation is 1/3 |x-3| +4=10.

The first step would be to cancel out the 1/3 but multiplying the reciprocal (flipping it) which is 3.

The equation is now |x-3| +12=30

Now, move the constant to the other side, in this case the constant would be 12.

Making the equation now: |x-3|=30-12

After this, combine like terms: |x-3|=18

Now make two cases with this equation |x-3|=18

|x-3|=18 and |x-3|=-18

Then solve those:

Your answer should be 21 and -15

User Cobaltduck
by
8.2k points
1 vote

Answer:

x = 21

x = -15.

Explanation:

The equation 1/3 |x-3| +4=10 can be solved as follows:

1/3 |x-3| = 10 - 4

1/3 |x-3| = 6

|x-3| = 6 × 3

|x-3| = 18

Now, we have two cases to consider:

Case 1: When positive

In this case, |x-3| = (x-3). Therefore, we have the following equation:

x - 3 = 18

x = 18 + 3

x = 21

Case 2: When negative

In this case, |x-3| = -(x-3). Therefore, we have the following equation:

-(x-3) = 18

x-3 = -18

x = - 18 + 3

x = -15

Therefore, the solutions to the equation are x=21 and x=-15.

User Yemi
by
8.5k points

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