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Consider the equation below.x3 – 3x2 – 4 = 1/x-1+ 5The solutions to the equation are approximately x=and x=

User Anatoly Strashkevich
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Question:

Solution:

Consider the following equation:


x^3-3x^2-4=(1)/(x-1)+5

this is equivalent to:


x^3-3x^2=(1)/(x-1)+5+4

that is:


x^3-3x^2=(1)/(x-1)+9

Multiplying both sides by (x-1), we obtain:


(x-1)(x^3-3x^2)=1+9(x-1)

this is equivalent to:


(x-1)x^3-3x^2(x-1)=1+9(x-1)

solving for x, we obtain that the correct solutions are:


x\text{ }\approx0.90672

and


x\approx\: 3.68875

Consider the equation below.x3 – 3x2 – 4 = 1/x-1+ 5The solutions to the equation are-example-1
User Jsalter
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