Answer:
The molarity of the HCl solution is approximately 26.67 M.
Step-by-step explanation:
To determine the molarity of the HCl (hydrochloric acid) solution, you can use the information provided. You know that 0.8 Molar NaOH (sodium hydroxide) is added to react with the HCl in the solution.
You can use the concept of stoichiometry and the balanced chemical equation for the reaction between NaOH and HCl, which is:
NaOH + HCl → NaCl + H2O
In this reaction, one mole of NaOH reacts with one mole of HCl to produce one mole of NaCl and one mole of water.
You added 0.8 moles of NaOH to the solution. Therefore, there were also 0.8 moles of HCl in the solution since the reaction is 1:1.
To find the molarity of the HCl solution, you need to know the volume of the HCl solution that the 0.8 moles of HCl are dissolved in. You mentioned that 30 mL of HCl is used.
Now, calculate the molarity of the HCl solution:
Molarity (M) = Moles of solute / Volume of solution (in liters)
Molarity of HCl = 0.8 moles / 0.030 L (since 30 mL is equal to 0.030 L)
Molarity of HCl = 26.67 M
So, the molarity of the HCl solution is approximately 26.67 M.