Question

The sum of three numbers is 132. The third number is 4 times the first. The second number is 6 less than the first. What are the numbers?

Answer 1

The first number (x) is 23.

The second number (y) is 17.

The third number (z) is 92.

Explanation:

Let:

The first number be "x."

The second number be "y."

The third number be "z."

We have three equations based on the given information:

x + y + z = 132 (The sum of the numbers is 132).

z = 4x (The third number is 4 times the first).

y = x - 6 (The second number is 6 less than the first).

Now we can solve for the numbers. Substituting the values from equations 2 and 3 into equation 1:

x + (x - 6) + 4x = 132

Combine like terms:

6x - 6 = 132

Add 6 to both sides:

6x = 138

Now, divide by 6:

x = 23

Now that we know the value of x, we can find y and z:

y = x - 6 = 23 - 6 = 17

z = 4x = 4 * 23 = 92