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(x^3+2x^2 −20x−33)÷(x+5)

User Belst
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2 Answers

1 vote

Answer: this would be x^2-3x-5 with a remainder of -8.

Explanation:

so this would be the correct answer btw dont forget the REMAINDER OF 8

User Shu Wu
by
8.5k points
2 votes

Answer:

Explanation:

To divide the polynomial (x^3+2x^2-20x-33) by (x+5), we can use long division. Here are the steps:

1. Begin by dividing the first term of the dividend (x^3) by the first term of the divisor (x). The result is x^2. Write this above the division symbol.

2. Multiply the entire divisor (x+5) by the result from step 1 (x^2). This gives you x^3+5x^2.

3. Subtract this result (x^3+5x^2) from the original dividend (x^3+2x^2-20x-33). This will cancel out the x^3 term, leaving you with -3x^2-20x-33.

4. Bring down the next term from the dividend, which is -20x.

5. Repeat steps 1-3 with the new expression (-3x^2-20x-33) and the divisor (x+5).

6. Dividing -3x^2 by x gives you -3x. Write this above the division symbol.

7. Multiply the entire divisor (x+5) by -3x. This gives you -3x^2-15x.

8. Subtract this result (-3x^2-15x) from the expression -3x^2-20x-33. This will cancel out the -3x^2 term, leaving you with -5x-33.

9. Bring down the next term from the dividend, which is -33.

10. Repeat steps 1-3 with the new expression (-5x-33) and the divisor (x+5).

11. Dividing -5x by x gives you -5. Write this above the division symbol.

12. Multiply the entire divisor (x+5) by -5. This gives you -5x-25.

13. Subtract this result (-5x-25) from the expression -5x-33. This will cancel out the -5x term, leaving you with -8.

14. There are no more terms to bring down from the dividend.

15. The final result is x^2-3x-5 with a remainder of -8.

Therefore, (x^3+2x^2-20x-33) divided by (x+5) is equal to x^2-3x-5 with a remainder of -8.

User Adam Kewley
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7.3k points