Final answer:
There are 24 ways to arrange five children on a slide if one of them always wants to go last.
Step-by-step explanation:
The number of ways five children can be arranged on a slide if one of them always wants to go last can be found using permutations. Since the miedoso child always wants to go last, there are four remaining children who can go in any order. The number of ways to arrange these four children is 4! (4 factorial), which is equal to 24.
Learn more about arranging children on a slide