Question

A train travels at a rate of 13 meters per second. Over the next 60 seconds, the speed of the train to 22 m/s. What is the average rate of acceleration of the train?

Answer 1

0.15 m/s^2

Step-by-step explanation:

A train runs at a rate of 13 meters per second.Over the next 60 seconds, the speed of the train to 22 m/s.

i.e,

• initial velocity or speed of the train is 13 m/s.
• Final velocity or speed of the train is 22 m/s
• time period is 22 m/s.

We are asked to determine the average rate of acceleration of the train. To calculate the rate of acceleration of the train we can kinematics equation,

Using first kinematics equation,

• v = u + at

Where, v denotes final Velocity, u denotes initial velocity, t denotes time and a denotes acceleration.

On substituting the required values in the above equation, we have

`\longrightarrow 22 = 13 + a (60)`

Subtract 13 from both sides,

`\longrightarrow 22 - 13 = a * 60`

`\longrightarrow 9 = a * 60`

Divide both sides by 60,

`\longrightarrow a = 0.15`

Hence, the average rate of acceleration of the train is 0.15 m/s^2