Answer:19.6J
Step-by-step explanation:
There are two ways of solving this problem.
1st, in terms of kinematics we can solve for final velocity and plug into the kinetic energy equation 1/2 mv^2.
Solve for final velocity
The ball will have a displacement of 10 m downward or -10 m
The initial velocity is 0
The acceleration is g = -9.8 m/s^2
We plug into the equation V_f^2=V_i^2+2(a)(displacement)
v_f^2= 0+2(-9.8)(-10)
vf=14 m/s
Now plug into Ke=(1/2)m(V^2)
Ke = (1/2)0.2(14^2)= 19.6 J
The second way we can solve is using conservation of energy
Gravitational potential energy (mgh) at max height equals Kinetic energy (1/2)mv^2at the ground.
mgh=1/2mv^2 =Ke
.2*9.8*10=Ke= 19.6 J