Answer:
Down and to the left will be in the third quadrant
tan θ = 9.04 / 6.68 = 1.35 and θ = 53.5 deg below the negative x-axis
So D = (180 + 53.5) (Dx^2 + Dy^2)^1/2
D = 11.2 tan 233.5
Or D = -6.68 i - 9.04 j
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