Question

8 What is the equation of a line

perpendicular to y = 3x + 4 that passes
through (-1, 6)?

Answer 1

y=-1/3x + 17/3

Explanation:

gradient(m)=3

gradient of the perpendicular line= -(1/3)

y-y1=m(x-x1)

Here,

y1=6

x1= -1

m=-1/3

y-6=-1/3(x-(-1))

y= -1/3x- 1/3 + 6

y=-1/3x + 17/3