Question

Find the distance d (P1, P2) between the points P, and P2.

P1 = (-2,5); P2 = (4,0)
(P4, P2) - (Type an exact answer, using radicals as needed.)

Answer 1

`√(61)` units

Explanation:

We are given that

`P_1=(-2,5)`

`P_2=(4,0)`

We have to find the distance d (P1, P2) between the points P, and P2

We know that

Distance between two points (x1,y1) and (x2,y2) i

=
`√((x_2-x_1)^2+(y_2-y_1)^2)`

Using the formula

The distance d (P1, P2) between the points P, and P2

=
`√((4-(-2))^2+(0-5)^2)`

The distance d (P1, P2) between the points P, and P2

`=√((4+2)^2+(-5)^2)`

The distance d (P1, P2) between the points P, and P2

=
`√(6^2+25)`

The distance d (P1, P2) between the points P, and P2

=
`√(61)` units