Question

Can you please help me out with a question

Answer 1

`\begin{gathered} \sin ce\text{ the diameter of marble is given then the marble is a sphere} \\ \text{from the question;} \\ \text{diameter = 62mm, this implies } \\ \text{radius = }(62)/(2)\text{ = 31mm} \\ \text{applying the formula for volume of sphere} \\ \text{volume of sphere = }(4)/(3)\pi r^3 \\ \text{volume of sphere = }(4)/(3)\text{ }*\text{ }(22)/(7)*31^3 \\ \text{volume of sphere = 124838.48}mm^3 \\ \text{volume of sphere }\cong124,838mm^3\text{ to the nearest cubed millimeter} \\ \\ \text{hence volume of marble = 124, 838mm}^3 \end{gathered}`
`\begin{gathered} \sin ce\text{ the marble cracked into equal pieces then} \\ \\ \text{volume of one piece = }\frac{\text{volume of sphere}}{2} \\ \text{volume of one piece = }(124,838)/(2)mm^3 \\ \text{volume of one piece = 62,419mm}^3\text{ to the nearest cubed millimeter} \end{gathered}`