Question

Passing through (-7,-8) and parallel to the line whose equation is y=-4x+4 I\write an equation for the line in point-slope form.

Answer 1

y = -4x - 36

Explanation:

m = -4

Point (-7,-8)

y - y = m ( x - x)

y - - 8 = - 4(x - - 7)

y + 8 = -4x - 28

y = -4x - 28 - 8

y = - 4x - 36

Answer 2

Answer:
`\pmb{y+8=-4(x+7)}`

Explanation:

We need to write the equation for a line that:

• passes through (-7,-8)
• is parallel to y = -4x + 4

Since the lines are parallel, their slope will be the same. Hence, both lines have a slope of -4.

Now we can use our point-slope formula:

`\bigstar\qquad\boldsymbol{\sf{y-y_1=m(x-x_1)}}`

Plug in the values:

`\bigstar\quad\boldsymbol{\sf{y-(-8)=-4(x-(-7)}}`

`\bigstar\qquad\boxed{\boldsymbol{\sf{y+8=-4(x+7)}}}`