(in liters).
Determine the moles of NaOH used:
Moles of NaOH
=
Molarity
×
Volume (L)
Moles of NaOH=Molarity×Volume (L)
Moles of NaOH
=
6.88
mol/L
×
(
267
mL
/
1000
)
Moles of NaOH=6.88mol/L×(267mL/1000)
Use the balanced chemical equation to find the moles of HNO₃:
The balanced equation for the neutralization reaction between NaOH and HNO₃ is:
NaOH
+
HNO₃
→
NaNO₃
+
H₂O
NaOH+HNO₃→NaNO₃+H₂O
Since the ratio of moles of NaOH to moles of HNO₃ is 1:1, the moles of HNO₃ are also equal to the moles of NaOH.
Determine the concentration of HNO₃:
Concentration of HNO₃
=
Moles of HNO₃
Volume (L)
Concentration of HNO₃=
Volume (L)
Moles of HNO₃
Concentration of HNO₃
=
Moles of NaOH
123
mL
/
1000
Concentration of HNO₃=
123mL/1000
Moles of NaOH
Now, you can plug in the values and calculate the concentration of HNO₃ in simple terms. Remember to perform the calculations using consistent units (e.g., convert mL to L).