Final answer:
The magnitude of the induced electromotive force (emf) in the single loop of wire can be calculated using Faraday's Law of Electromagnetic Induction, resulting in a value of approximately 855.67 Volts.
Step-by-step explanation:
The principle narrated in the question is related to Faraday's Law of Electromagnetic Induction, which is a fundamental concept in physics. It states that the induced electromotive force (emf) in a closed loop of wire is equal to the rate of change of the magnetic flux through the loop.
Given that the magnetic flux changes from 8.3 Webers to 0 Webers in 9.7 milliseconds, we can use Faraday's law to calculate the change in magnetic flux (ΔΦ), which is 8.3 Webers - 0 Webers = 8.3 Webers. The time change (Δt) is 9.7 millisecond = 0.0097 seconds. Therefore, the induced emf can be calculated as follows:
Emf = - ΔΦ/ Δt
= - (8.3 Webers)/ (0.0097 seconds)
= - 855.67 volts.
The negative sign indicates that the induced emf acts in such a way to oppose the change in magnetic flux, according to Lenz's law, but the question asks for the magnitude of the emf, so we take the absolute value: 855.67 Volts.
Learn more about Electromagnetic Induction