176k views
2 votes
Single-slit diffraction maximum. Light of wavelength 750 nm passes through a slit 1.0 x 10⁻³mm wide. How wide is the central maximum (a) in degrees

User DMozzy
by
8.2k points

1 Answer

4 votes

The central maximum in the single-slit diffraction pattern can be calculated using the formula:

```
λ / w
```

Here, `λ` represents the wavelength of light and `w` represents the width of the slit.

First, we need to convert the provided values of `λ` and `w` into consistent units. The wavelength λ = 750 nm needs to be converted to meters. Knowing that 1 nm = 1e-9 m, we can do this by multiplying:

750 nm * 1e-9 = 750 * 10^-9 m.

Likewise, the slit width w is given as 1.0 x 10^⁻³ mm. To convert this to meters, we use the conversion factor 1 mm = 1e-3 m, leading to:

1.0 * 10^-3 mm * 1e-3 = 1.0 * 10^-3 * 10^-3 m.

Substituting λ = 750 * 10^-9 m and w = 1.0 * 10^-3 * 10^-3 m into the formula, we find the angular width of the central maximum in radians:

λ / w = (750 * 10^-9 m) / (1.0 * 10^-3 * 10^-3 m) = 0.75 radians.

Next, we convert the angular width from radians to degrees. The conversion factor is 180 degrees/π radians, so we multiply:

0.75 radians * (180/π) = 42.97 degrees.

So, the angular width of the central maximum caused by diffraction of 750 nm light through a 1.0 x 10⁻³mm-wide slit is approximately 0.75 radians, which is equivalent to approximately 42.97 degrees.

User Bgura
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.