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A ball rolls off a table with an initial horizontal velocity of 2.5 m/s. The ball lands 0.75 meters away from the base of the table.

How long does it take the ball to hit the ground?
seconds (nearest hundredth)
What is the height of the table (dy)?
m (nearest hundredth)

1 Answer

5 votes

Final answer:

The ball takes 0.3 seconds to hit the ground and the height of the table is 0.44 meters.


Step-by-step explanation:

To determine the time it takes for the ball to hit the ground, we can use the equation for horizontal motion:

Dx = Vx * t

where Dx is the horizontal distance traveled, Vx is the initial horizontal velocity, and t is the time.

Given that Dx = 0.75 m and Vx = 2.5 m/s, we can rearrange the equation to solve for t:

t = Dx / Vx = 0.75 m / 2.5 m/s = 0.3 seconds (nearest hundredth).

To find the height of the table (dy), we can use the equation for vertical motion under constant acceleration (assuming there is no air resistance or other external forces):

dy = 0.5 * g * t^2

where dy is the vertical distance, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time. Substituting the time we found earlier (t = 0.3 seconds) into the equation, we can calculate the height of the table as follows:

dy = 0.5 * 9.8 m/s^2 * (0.3 s)^2 = 0.44 m (nearest hundredth).


Learn more about Horizontal and vertical motion

User Ryan Schaefer
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