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Write the quotient in standard form. 10 − 20i 1 − 3i

User Pabce
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1 Answer

4 votes

Answer:

Explanation:

you mean
(10-20 i)/(1-3i)


(10-20\iota)/(1-3 \iota) =(10-20 \iota)/(1-3 \iota) *(1+3 \iota)/(1+3 \iota) \\=(10+30 \iota-20 \iota-60 \iota^2)/(1-9 \iota^2) \\=(10+10 \iota-60(-1))/(1-9(-1)) \\=(70+10 \iota)/(10) \\=7+ \iota

User Headcrab
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