Question

(50 POINTS PLEASE HELP) Kira is standing 118 m from a building. The angle of elevation from where she is standing on the ground to the top of the building is 62°.

How tall is the building?

Answer 1

Explanation:

let the height of building=h

`(h)/(118) =\tan ~62\\h=118 * \tan~62 \approx ~221.93~m`

Answer 2

Approximately 222 m

Explanation:

In order to find the height of the building, we can use trigonometry.

Given that Kira is standing 118 meters from the building and the angle of elevation is 62°, we can use the tangent function.

The tangent of an angle in a right triangle is equal to the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle.

In this case, the height of the building is the side opposite the angle, and the distance Kira is standing from the building (118 meters) is the side adjacent to the angle.

So, we can use the formula:

`\sf \tan(\textsf{Angle}) = \frac{\textsf{Height}}{\textsf{distance}}`

Substitute the values:

`\tan(62°) = \frac{\text{Height}}{118}`

Now, solve for the height:

`\sf \textsf{Height} = 118 \cdot \tan(62°)`

Using a calculator:

`\sf \textsf{Height} \approx 118 \cdot 1.8807264653463`

`\sf \textsf{Height} \approx 221.92572291086`

`\sf \textsf{Height} \approx 222\textsf{( in nearest whole number)}`

So, the height of the building is approximately 222 meters.