Question

A drug is administered every 12 hours in doses of 10mg. The drug is neutralized at an exponential rate of k-0.2. Not all of the drug is neutralized before the next dose is administered. The amount of drug A(t) at time thours in the patient's system during the third dosing period is given by: A(t)=(10+10e⁻²/⁴ +10e⁻⁴/⁸)e⁻⁰.²⁽ᵗ⁻²⁴⁾ What is the limit of the residual amount of drug in the patient's system at the end of the third dosing period?

Answer 1

To find the residual amount of drug in the patient's system at the end of the third dosing period, evaluate the given expression for A(t) at t = 36 hours.

Step-by-step explanation:

The residual amount of drug in the patient's system at the end of the third dosing period can be found by evaluating the given expression for A(t) at t = 36 hours:

A(36) = (10 + 10e⁻²/⁴ + 10e⁻⁴/⁸)e⁻⁰.²⁽³⁶⁻²⁴⁾

Substituting the value of t into the equation, we have:

A(36) = (10 + 10e⁻²/⁴ + 10e⁻⁴/⁸)e⁻⁰.²²

Calculating the value of A(36) will give us the limit of the residual amount of drug in the patient's system at the end of the third dosing period.

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