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The length of a rectangle is 10 cm, and its perimeter is less than 34 cm. What can you conclude about its width?

User CentAu
by
8.9k points

2 Answers

2 votes

Answer:

W < 7

Explanation:

The perimeter (P) of a rectangle can be calculated using the formula:


\sf P = 2L + 2W

  • Where L is the length of the rectangle, and W is the width.
  • In this case, the rectangle's length is 10 cm, so L = 10
  • The problem states that the perimeter is less than 34 cm.

Therefore, we can write:


\sf2L + 2W < 34

Substitute the value of L


\sf 2(10) + 2W < 34

Now, simplify the equation:


\sf 20 + 2W < 34

Subtract 20 from both sides:


\sf 2W < 14

Finally, divide by 2:


\sf W < 7

So, the width of the rectangle must be less than 7 cm in order for the perimeter to be less than 34 cm.

User Ishwor Khanal
by
8.7k points
2 votes

Answer:

The width must be less than 7.

Explanation:

We know that the perimeter of a rectangle is given by

P = 2(l+w)

The perimeter is less than 34

34 > 2 (l+w)

34 > 2 (10+w)

Divide each side by 2

17 > 10+w

Subtract 10 from each side

17-10 > w

7 > w

The width must be less than 7.

User Quique
by
8.3k points

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