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Find the four second partial derivatives. 8. f(x,y)=x +y-eˣ+ʸ

User Coree
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To find the four second partial derivatives of the function f(x,y)=x + y - e^(x+y), you can begin by finding the first and second partial derivatives with respect to both x and y.

1. Partial Derivative of f with respect to x:

The partial derivative of f with respect to x (symbolized as f_x) involves taking the derivative of f(x,y) with regard to x, while treating y as a constant. This yields:

f_x = 1 - e^(x+y)

2. Second Partial Derivative of f with respect to x:

This involves deriving f_x with respect to x (symbolized as f_xx or ∂²f/∂x²). This gives us:

f_xx = -e^(x+y)

3. Partial Derivative of f with respect to y:

The process is similar to (1), but this time holding x as constant, resulting in:

f_y = 1 - e^(x+y)

4. Second Partial Derivative of f with respect to y:

Again, similar to (2), but this time deriving f_y with respect to y (symbolized as f_yy or ∂²f/∂y²). The end result is:

f_yy = -e^(x+y)

5. Cross Partial Derivatives:

These derivatives involve deriving with respect to both x and y. The order of the derivatives does not matter due to Schwarz's Theorem, which states that the cross derivatives of a sufficiently smooth function are equal, that is, f_xy = f_yx.

Computing f_xy, which involves taking the derivative of f_x with respect to y, gives:

f_xy = -e^(x+y)

Similarly, computing f_yx by taking the derivative of f_y with respect to x also gives:

f_yx = -e^(x+y)

This implies that the second cross partial derivatives of the function f are both equal to -e^(x+y).

In conclusion, the second partial derivatives of the function f(x,y) are as follows: f_xx = f_yy = f_xy = f_yx = -e^(x+y)

User Jason Holloway
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