Question

jonathan is three times as old as his son is. twelve years ago, he was six times as old as his son was. find the present age of each

Answer 1

Given the conditions in the problem, we can set up two equations. Solving for these, it can be concluded that Jonathan is 54 years old, and his son is 18 years old.

Step-by-step explanation:

In this problem, we are given two facts:

1. Jonathan is three times as old as his son.

2. 12 years ago, Jonathan was six times as old as his son was then.

We can set up two equations from these facts.

Let J represent Jonathan's current age and S represent his son's current age:

• J = 3S (Jonathan is three times as old as his son)
• J - 12 = 6(S - 12) (12 years ago, Jonathan was six times as old as his son was)

Solving these two equations, we get:

J = 3S becomes S = J/3

Replace S in the second equation we get J - 12 = 6(J/3 - 12), solving gives J = 54

Substitute J = 54 into the first equation we get S = 54/3 = 18.

So, Jonathan is 54 and his son is 18.

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