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Given that 3x²+bx +10=a(x+3)²+c for all values of x, find the values of the constants a,b and c

User Kenee
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1 Answer

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To solve this problem, we would first expand the right hand side of the equation making the equation as follows:

3x² + bx + 10 = ax² + 6ax + 9a + c

Following this, we need to make sure we match coefficients on both sides of the equation for each power of x.

Matching the coefficient of x²:

On the left hand side, the coefficient of x² is 3
On the right hand side, the coefficient of x² is a

So, we have:

3 = a
So, a = 3.

Next, we match the coefficients of x:

On the left hand side, we have b
On the right hand side, we have 6a = 6*3 = 18

So, we have:

b = 18

Lastly, we match the constant terms:

On the left hand side, we have 10
On the right hand side, we have 9a + c = 9*3 + c = 27 + c

So we have:

10 = 27+c
Rearranging, we'll get:
c = 10 - 27 = -17

So, the solution for the symbols a, b, and c are 3, 18, and -17 respectively.

User Shane Courtrille
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