Answer:
0.57926
Explanation:
Given that :
Mean, m = 6
Standard deviation, s = 1
P(x < 6.2)
Obtain the Zscore :
Zscore = (x - m) / s
Zscore = (6.2 - 6) / 1
Zscore = 0.2
P(Z < 0.2) = 0.57926 (Z probability calculator)
Probability of having head breadth less than 6.2 is 0.57926