Answer:
Explanation:
You can create a system of equations to solve this problem.
Let C = the number of chickens
Led P = the number of pigs
"A farmer raises chickens and pigs-53 animals in total" translates into the equation C+P=53
If each chicken has 2 feet and each pig has 4 feet, then "he saw 146 feet in the morning" can be written as 2C + 4P = 146
If you solve for C in the first equation (C=53-P) then you can substitute that into the second equation and solve for the number of pigs.
2(53-P) + 4P =146
106 - 2P + 4P = 146 (sub 106 from each side and combine like terms)
2P = 40 (divide both sides by 2)
P = 20.
If we know that there are 20 Pigs, we can plug that information into the first equation to solve for the number of chickens:
C + 20 = 53
C = 33
So there are 20 pigs and 33 chickens.