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Lines a and b are cut by transversal f. At the intersection of lines f and a, the top left angle is 96 degrees. At the intersection of lines b and f, the bottom right angle is (6 x minus 36) degrees. What must be the value of x so that lines a and b are parallel lines cut by transversal f? 10 20 22 32

2 Answers

4 votes

Answer:

22

Explanation:

edge

User Stefan Repcek
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3.8k points
10 votes

Answer: 22

Explanation:

Lines a and b are cut by transversal f.

Then from the given information,


6x-36=96 [ If two parallel lines are cut by a transversal then, the alternate exterior angles are equal. ]


\Rightarrow\ 6x=96+36\\\\\Rightarrow\ 6x=132\\\\\Rightarrow\ x=(132)/(6)\\\\\Rightarrow\ x=22

Hence, the value of x so that lines a and b are parallel lines cut by transversal = 22

Lines a and b are cut by transversal f. At the intersection of lines f and a, the-example-1
User Ali Akhtari
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4.1k points