Question

1. Light travels from air into an optical fiber with an index of refraction of 1.44. (a) If the angle of incidence on the end of the fiber is 22 degree, what is the angle of refraction inside the fiber?

Answer 1

The angle of refraction of light inside the fiber is 15.12 degrees. This is calculated using Snell's law, which uses the angle of incidence and the indices of refraction for the two mediums.

Step-by-step explanation:

The student is asking about the phenomenon of light refraction, which can be resolved by using Snell's law. Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the velocity of light in the original medium to the velocity of light in the refracting medium, or alternatively, the ratio of the refractive indices of the two media.

Given that the index of refraction n1 for air is approximately 1.00, the angle of incidence θ1 is 22 degrees, and the index of refraction n2 for the optical fiber is 1.44, we can now plug these values into Snell's law:

n1 * sin(θ1) = n2 * sin(θ2)

After rearranging for θ2 and substituting the given values, we obtain an angle of refraction θ2 that equals to 15.12 degrees inside the optical fiber.

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