Question

The standard heat of combustion is shown in the following chemical equation CgH 20 (g) + 140 2(g) 9CO 2(g) + 10H 2 o (1) delta

Answer 1

The given question is incomplete. The complete question is:

The standard heat of combustion is shown in the following chemical equation
`C_9H_(20)(g)+14O_2(g)\rightarrow 9CO_2(g)+10H_2O`
`\Delta H_(rxn)=-6125.21kJ/mol`. If 130 g of nonane combusts , how much heat is released?

Answer: 6211.21 kJ

Step-by-step explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of 1 mole of nonane = 6125.21 kJ

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number
`6.023* 10^(23)` of particles.

1 mole of nonane
`(C_9H_(20))` weighs = 128.2 g

Thus we can say:

128.2 g of nonane on combustion releases = 6125.21 kJ

Thus 130 g of
`C_4H_(10)` on combustion releases =
`(6125.21)/(128.2)* 130=6211.21kJ`

Thus the heat of combustion of 130 g of nonane is 6211.21 kJ