Question

Write the third and fifth term of an arithmetic sequence whose fourth term is 9 and the common difference is 2

Answer 1

a₃ = 7 , a₅ = 11

Explanation:

Any term in an arithmetic sequence (
`a_(n)` ) is found by adding the common difference (d) to the preceding term , that is

`a_(n)` =
`a_(n-1)` + d ( n is the term number )

given a₄ = 9 and d = 2 , then

a₅ = a₄ + d = 9 + 2 = 11

to find the preceding term to a₄ , that is a₃ , then subtract d , that is

a₃ = a₄ - d = 9 - 2 = 7