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Given the following functions,
‚ƒ(x) = 3x² + x − 2 and g(x)=4-x
Find f (-2) +2g (6)

Given the following functions, ‚ƒ(x) = 3x² + x − 2 and g(x)=4-x Find f (-2) +2g (6)-example-1
User Mozway
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1 Answer

4 votes

Answer:

Therefore, f(-2) + 2g(6) is equal to 4.

Explanation:

To find f(-2) + 2g(6), we need to evaluate the functions f(x) and g(x) at the given values and perform the calculations.

Given:

ƒ(x) = 3x² + x - 2

g(x) = 4 - x

First, let's find ƒ(-2):

ƒ(-2) = 3(-2)² + (-2) - 2

= 3(4) - 2 - 2

= 12 - 2 - 2

= 8

Next, let's find g(6):

g(6) = 4 - 6

= -2

Now we can calculate f(-2) + 2g(6):

f(-2) + 2g(6) = 8 + 2(-2)

= 8 - 4

= 4

Therefore, f(-2) + 2g(6) is equal to 4.

User Cristian Reyes
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