Answer:
x = -3, x = 5
Explanation:
log(x^2 - 2x) = log 15
e^(log(x^2 - 2x)) = e^(log(15))
x^2 - 2x = 15
x^2 - 2x - 15 = 0
x^2 - 5x + 3x - 15 = 0
x(x-5) + 3(x-5) = 0
(x+3)(x-5) = 0
(x+3) = 0 (x - 5) = 0
x = -3 x = 5
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