10.5k views
1 vote
How many moles of CO2 are produced when 5.45 mol of ethane is burned in an excess of oxygen

1 Answer

4 votes

Answer:

Step-by-step explanation:

The balanced chemical equation for the combustion of ethane (\(C_2H_6\)) in oxygen (\(O_2\)) is as follows:

\[2C_2H_6 + 7O_2 \rightarrow 4CO_2 + 6H_2O\]

This equation tells us that when 2 moles of ethane (\(C_2H_6\)) react with 7 moles of oxygen (\(O_2\)), it produces 4 moles of carbon dioxide (\(CO_2\)).

To find out how many moles of \(CO_2\) are produced when 5.45 moles of ethane are burned, you can set up a proportion using the mole ratio from the balanced equation:

\[\frac{5.45 \text{ moles of } C_2H_6}{2 \text{ moles of } C_2H_6} = \frac{x \text{ moles of } CO_2}{4 \text{ moles of } CO_2}\]

Now, solve for \(x\ ( \text{moles of } CO_2)\):

\[x = \frac{5.45 \times 4}{2} = 10.9 \text{ moles of } CO_2\]

So, when 5.45 moles of ethane are burned in excess oxygen, 10.9 moles of carbon dioxide are produced.

User Maddy Sharma
by
8.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.