The possible numbers of hours per week they will practice is any value between 4 and 8.375, inclusive.
To find the possible numbers of hours per week the Keytones Choir will practice for the remaining 8 weeks, we need to consider the given constraints.
The total number of hours they want to practice is at least 43 and at most 67.
They have already practiced for 11 hours, so the remaining number of hours they need to practice is:
Total number of hours - Hours already practiced = 43 - 11 = 32
Now, let's solve for x, which represents the number of hours per week they will practice.
To practice for 8 weeks, the total number of hours they will practice is:
Number of hours per week * Number of weeks = 8x
Since they want to practice at least 32 hours and at most 67 hours, we can set up a compound inequality:
32 ≤ 8x ≤ 67
Now, we can solve this compound inequality for x by dividing each term by 8:
32/8 ≤ x ≤ 67/8
Simplifying further, we get:
4 ≤ x ≤ 8.375
Keep in mind that since the number of hours per week needs to be a whole number, the Keytones Choir can practice for 4, 5, 6, 7, or 8 hours per week.
Complete Question:
The Keytones Choir is practicing for a show. To feel prepared, they will practice for at least 43 hours. They also don't want to overuse their voices, so they will practice for at most 67 hours. So far, they have practiced a total of 11 hours. Let x be the number of hours per week they will practice for the remaining 8 weeks. (Suppose they will decide to practice the same amount of time each week.)
(a) Find the possible numbers of hours per week they will practice. Write your answer as a compound inequality solved for x.