Final answer:
The volume occupied by 14.1 g of argon gas at a pressure of 1.50 atm and a temperature of 354 K is approximately 6.02 L.
Step-by-step explanation:
To find the volume occupied by the argon gas, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
First, we need to convert the mass of argon gas (14.1 g) to moles using the molar mass of argon (39.95 g/mol). We divide the mass by the molar mass to get the number of moles, which is approximately 0.353 moles.
Next, we can rearrange the ideal gas law equation to solve for volume (V): V = nRT / P. Plugging in the values we have, V = (0.353 moles)(0.0821 L·atm/mol·K)(354 K) / (1.50 atm). Solving this equation gives us the volume, which is approximately 6.02 L.
Learn more about Volume of a gas