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Evaluate: xy+2x^2, if x=0.1 and y=9.8
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Evaluate: xy+2x^2, if x=0.1 and y=9.8

User Vearutop
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2 Answers

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Try Photomath! I always use the app for evaluating
User David Hoffman
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11 votes

Answer: 1

Explanation:


(0.1)(9.8)+2(0.1)^2\\0.98+0.02=1

User Traninho
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