Question

What volume (in mL) of NH3 will 4.90 g of NH3 occupy at 0.98 atm and 23°C?

Answer 1

Answer: 8100 mL

Step-by-step explanation:

4.9 grams of ammonia is equal to 0.3266 moles of ammonia.

23 degrees Celsius is equal to 296 degrees Kelvin.

Using the ideal gas law,

`(0.98)(V)=(0.3266)(0.821)(296)\\\\V=81 \text{ L}`