Question

A 0.10 kg mass vibrates in the X-direction without friction at the end of a massless horizontal spring for which k = 10 N/m. The mass is displace m from equilibrium and released. The angular frequency of the mass is A 0.01 rad/s B 1 rad/s C 3.14 rad/s D 3162 rad/s E None of these F 00316 rad/s

Answer 1

The correct answer is E, None of these.

Here's how we determine the angular frequency:

We're working on a simple harmonic oscillator, for this scenario a mass on a spring. The angular frequency, often denoted as omega (ω), is computed using the formula

```
ω = sqrt(k/m)
```

Where k is the spring constant, and m is the mass.

From the given, we know that k = 10 N/m and that m = 0.1 kg.

Substituting the values into the formula, we get:

```
ω = sqrt(10 / 0.1)
```

Evaluating this with a calculator (or by hand), we find that ω = 10 rad/s.

So, the angular frequency of the mass when displaced and released is 10 rad/s. This does not match with any of the given alternatives, and so the correct option is E, None of these.